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I am creating an iPhone app and I need to convert a single digit number into an integer.
My code has a variable called char that has a type Character, but I need to be able to do math with it, therefore I think I need to convert it to a string, however I cannot find a way to do that.
605
Using Int initializer Swift provides the function of integer initializers using which we can convert a string into an Int type. To handle non-numeric strings, we can use nil coalescing using which the integer initializer returns an optional integer.
Swift – Check if Variable/Object is Int To check if a variable or object is an Int, use is operator as shown in the following expression. where x is a variable/object. The above expression returns a boolean value: true if the variable is an Int, or false if not an Int.
To convert a string to an array, we can use the Array() intializer syntax in Swift. Here is an example, that splits the following string into an array of individual characters. Similarly, we can also use the map() function to convert it. The map() function iterates each character in a string.
In the latest Swift versions (at least in Swift 5) there is a more straighforward way of converting Character instances. Character has property wholeNumberValue which tries to convert a character to Int and returns nil if the character does not represent and integer.
let char: Character = "5" if let intValue = char.wholeNumberValue { print("Value is \(intValue)") } else { print("Not an integer") } With a Character you can create a String. And with a String you can create an Int.
let char: Character = "1" if let number = Int(String(char)) { // use number } If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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