Is it possible to let function funcWithNonChanResult
have the following interface:
func funcWithNonChanResult() int {
And if I want it to use function funcWithChanResult
with the interface:
func funcWithChanResult() chan int {
In other words, can I somehow convert chan int
to int
? Or I must have chan int
result type in all the functions which use funcWithChanResult
?
Currently, I tried these methods:
result = funcWithChanResult()
// cannot use funcWithChanResult() (type chan int) as type int in assignment
result <- funcWithChanResult()
// invalid operation: result <- funcWithChanResult() (send to non-chan type int)
Full code:
package main
import (
"fmt"
"time"
)
func getIntSlowly() int {
time.Sleep(time.Millisecond * 500)
return 123
}
func funcWithChanResult() chan int {
chanint := make(chan int)
go func() {
chanint <- getIntSlowly()
}()
return chanint
}
func funcWithNonChanResult() int {
var result int
result = funcWithChanResult()
// result <- funcWithChanResult()
return result
}
func main() {
fmt.Println("Received first int:", <-funcWithChanResult())
fmt.Println("Received second int:", funcWithNonChanResult())
}
Playground
A chan int
is a channel of int
values, it is not a single int
value but a source of int
values (or also a target, but in your case you use it as source).
So therefore you can't convert chan int
to int
. What you can do and probably what you mean is use a value (of type int
) received from a chan int
as an int
value.
This is not a problem:
var result int
ch := funcWithChanResult()
result = <- ch
Or more compact:
result := <- funcWithChanResult()
Combine this with the return
statement:
func funcWithNonChanResult() int {
return <-funcWithChanResult()
}
Output (as expected):
Received first int: 123
Received second int: 123
Try your modified, working example on the Go Playground.
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