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In C is there a way to convert an ASCII value typed as an int into the the corresponding ASCII character as a char?
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You can use one of these methods to convert number to an ASCII / Unicode / UTF-16 character: You can use these methods convert the value of the specified 32-bit signed integer to its Unicode character: char c = (char)65; char c = Convert. ToChar(65);
You must first convert the character to its ASCII value. In LiveCode, this is done with the charToNum function. Converting a number to the corresponding character is done with the numToChar function. The first of these statements converts a number to a character; the second converts a character to its ASCII value.
Below are the implementation of both methods: Using ASCII values: ASCII value of uppercase alphabets – 65 to 90. ASCII value of lowercase alphabets – 97 to 122.
It can be observed that ASCII value of digits [0 – 9] ranges from [48 – 57]. Therefore, in order to print the ASCII value of any digit, 48 is required to be added to the digit. Below is the implementation of the above approach: C++
You can assign int to char directly.
int a = 65;
char c = a;
printf("%c", c);
In fact this will also work.
printf("%c", a); // assuming a is in valid range
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