convert an integer number into an array

Question

I am trying to convert an integer number in C into an array containing each of that number's digits

i.e. if I have

int number = 5400

how can I get to

int numberArray[4]

where

numberArray[0] = 0;
numberArray[1] = 0;
numberArray[2] = 4;
numberArray[3] = 5;

Any suggestions gratefully received.

Answer 1

Try this,

void initialise_array(int *a, int size, int num) {
    for (int i = 0; i < size; ++i, num /= 10)
        a[(size - 1) - i] = num % 10;
}

Answer 2

Hint: Take a look at this earlier question "Sum of digits in C#". It explains how to extract the digits in the number using several methods, some relevant in C.

From Greg Hewgill's answer:

/* count number of digits */
int c = 0; /* digit position */
int n = number;

while (n != 0)
{
    n /= 10;
    c++;
}

int numberArray[c];

c = 0;    
n = number;

/* extract each digit */
while (n != 0)
{
    numberArray[c] = n % 10;
    n /= 10;
    c++;
}