Convert a list of bytes to a byte string

Question

I have the following list of bytes:

[b'S', b'\x00', b't', b'\x00', b'a', b'\x00', b'n', b'\x00', b'd', b'\x00', b'a', b'\x00', b'r', b'\x00', b'd', b'\x00', b'F', b'\x00', b'i', b'\x00', b'r', b'\x00', b'm', b'\x00', b'a', b'\x00', b't', b'\x00', b'a', b'\x00', b'.', b'\x00', b'i', b'\x00', b'n', b'\x00', b'o', b'\x00', b'y', b'\x02', b'\x03', b'S', b'\x00', b't', b'\x00', b'a', b'\x00', b'n', b'\x00', b'd', b'\x00', b'a', b'\x00', b'r', b'\x00', b'd', b'\x00', b'F', b'\x00', b'i', b'\x00', b'r', b'\x00', b'm', b'\x00', b'a', b'\x00', b't', b'\x00', b'a', b'\x00', b'.', b'\x00', b'i', b'\x00', b'n', b'\x00', b'o', b'\x00', b'y', b'\x02', b'\x03', b'S', b'\x00', b't', b'\x00', b'a', b'\x00', b'n', b'\x00', b'd', b'\x00', b'a', b'\x00', b'r', b'\x00', b'd', b'\x00', b'F', b'\x00', b'i', b'\x00', b'r', b'\x00', b'm', b'\x00', b'a', b'\x00', b't', b'\x00', b'a', b'\x00', b'.', b'\x00', b'i', b'\x00', b'n', b'\x00', b'o', b'\x00', b'y', b'\x02', b'\x03', b'S', b'\x00', b't', b'\x00', b'a', b'\x00', b'n', b'\x00', b'd', b'\x00', b'a', b'\x00', b'r',

Is there a simple way for me to convert that into one long byte? I guess techincally called a bytestring (though I am not sure about that).

Note, I looked here but it does not work for me. Also, is the correct term for one long byte object (such as b'\f\x04\55') a byte object or something else?

Answer 1

Use bytes.join:

>>> b = [b'S', b'\x00', b't', b'\x00', b'a']
>>> b''.join(b)  # b'': separator
b'S\x00t\x00a'

Answer 2

bytes and bytearray objects have the join method:

In [37]: b''.join([b'S', b'\x00', b't', b'\x00', b'a', b'\x00', b'n', b'\x00', b'd', b'\x00'])
Out[37]: b'S\x00t\x00a\x00n\x00d\x00'