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i have a little problem with my script, where i need to convert ip in form 'xxx.xxx.xxx.xxx' to integer representation and go back from this form.
def iptoint(ip): return int(socket.inet_aton(ip).encode('hex'),16) def inttoip(ip): return socket.inet_ntoa(hex(ip)[2:].decode('hex')) In [65]: inttoip(iptoint('192.168.1.1')) Out[65]: '192.168.1.1' In [66]: inttoip(iptoint('4.1.75.131')) --------------------------------------------------------------------------- error Traceback (most recent call last) /home/thc/<ipython console> in <module>() /home/thc/<ipython console> in inttoip(ip) error: packed IP wrong length for inet_ntoa` Anybody knows how to fix that?
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To convert, or cast, a string to an integer in Python, you use the int() built-in function. The function takes in as a parameter the initial string you want to convert, and returns the integer equivalent of the value you passed.
The most Pythonic way to convert a list of strings to a list of ints is to use the list comprehension [int(x) for x in strings] . It iterates over all elements in the list and converts each list element x to an integer value using the int(x) built-in function.
In Python an strings can be converted into a integer using the built-in int() function. The int() function takes in any python data type and converts it into a integer.
#!/usr/bin/env python import socket import struct def ip2int(addr): return struct.unpack("!I", socket.inet_aton(addr))[0] def int2ip(addr): return socket.inet_ntoa(struct.pack("!I", addr)) print(int2ip(0xc0a80164)) # 192.168.1.100 print(ip2int('10.0.0.1')) # 167772161 Python 3 has ipaddress module which features very simple conversion:
int(ipaddress.IPv4Address("192.168.0.1")) str(ipaddress.IPv4Address(3232235521)) If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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