I've managed to do this using:
dft = pd.DataFrame.from_dict({
0: [50, 45, 00, 00],
1: [53, 48, 00, 00],
2: [56, 53, 00, 00],
3: [54, 49, 00, 00],
4: [53, 48, 00, 00],
5: [50, 45, 00, 00]
}, orient='index'
)
Done like this, the constructor looks just like the DataFrame making it easy to read/edit:
>>> dft
0 1 2 3
0 50 45 0 0
1 53 48 0 0
2 56 53 0 0
3 54 49 0 0
4 53 48 0 0
5 50 45 0 0
But the DataFrame.from_dict constructor doesn't have a columns parameter, so giving the columns sensible names takes an additional step:
dft.columns = ['A', 'B', 'C', 'D']
This seems clunky for such a handy (e.g. for unit tests) way to initialise DataFrames.
So I wonder: is there a better way?
Alternatively you could use DataFrame.from_items()
to construct the DataFrame from your dictionary; this allows you to pass in the column names at the same time.
For example, if d
is your dictionary:
d = {0: [50, 45, 0, 0],
1: [53, 48, 0, 0],
2: [56, 53, 0, 0],
3: [54, 49, 0, 0],
4: [53, 48, 0, 0],
5: [50, 45, 0, 0]}
The data is d.items()
and the orient is again 'index'
. The dictionary keys become the index values:
>>> pd.DataFrame.from_items(d.items(),
orient='index',
columns=['A','B','C','D'])
A B C D
0 50 45 0 0
1 53 48 0 0
2 56 53 0 0
3 54 49 0 0
4 53 48 0 0
5 50 45 0 0
In Python 2 you can use d.iteritems()
to yield the contents of the dictionary to avoid creating another list in memory.
One way to do that is the following:
df = pd.DataFrame.from_dict({
0: {"A":50, "B":40},
1: {"A":51, "B":30}}, orient='index')
However, for quick test initialization I would probably prefer your way + then setting the columns.
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