Using ggplot()
, I am trying to plot the results of an ANCOVA in which slopes of the two linear components are equal: i.e., lm(y ~ x + A)
. The default behavior for geom_smooth(method = "lm")
is to plot separate slopes and intercepts for each level of each factor. For example, with two levels of A
library(ggplot2)
set.seed(1234)
n <- 20
x1 <- rnorm(n); x2 <- rnorm(n)
y1 <- 2 * x1 + rnorm(n)
y2 <- 3 * x2 + (2 + rnorm(n))
A <- as.factor(rep(c(1, 2), each = n))
df <- data.frame(x = c(x1, x2), y = c(y1, y2), A = A)
p <- ggplot(df, aes(x = x, y = y, color = A))
p + geom_point() + geom_smooth(method = "lm")
I can fit the ANCOVA separately with lm()
and then use geom_abline()
to manually add the lines. This approach has a couple of drawbacks like having the lines extend beyond the range of the data and manually specify the colors.
fm <- lm(y ~ x + A, data = df)
summary(fm)
a1 <- coef(fm)[1]
b <- coef(fm)[2]
a2 <- a1 + coef(fm)[3]
p + geom_point() +
geom_abline(intercept = a1, slope = b) +
geom_abline(intercept = a2, slope = b)
I know ancova()
in the HH package automates the plotting, but I don't really care for lattice graphics. So I am looking for a ggplot()
-centric solution.
library(HH)
ancova(y ~ x + A, data = df)
Is there a method to accomplish this using ggplot()
? For this example, A
has two levels, but I have situations with 3, 4, or more levels. The formula
argument to geom_smooth()
doesn't seem to have the answer (as far as I can tell).
For completeness, this works:
library(ggplot2)
set.seed(1234)
n <- 20
x1 <- rnorm(n); x2 <- rnorm(n)
y1 <- 2 * x1 + rnorm(n)
y2 <- 3 * x2 + (2 + rnorm(n))
A <- as.factor(rep(c(1, 2), each = n))
df <- data.frame(x = c(x1, x2), y = c(y1, y2), A = A)
fm <- lm(y ~ x + A, data = df)
p <- ggplot(data = cbind(df, pred = predict(fm)),
aes(x = x, y = y, color = A))
p + geom_point() + geom_line(aes(y = pred))
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