#include <iostream>
#include <array>
int main(int argc, char **argv) {
constexpr const std::array<int, 2> arr {{ 0, 1 }};
constexpr const int arr2[] = { 0, 1};
static_assert(arr[0] == arr2[0], "asdf");
static_assert(arr[1] == arr2[1], "asdfasdf");
return 0;
}
When compiled with gcc 4.8.2
and 4.9.1
using g++ test.cpp --std=c++11
, the compilation succeeds.
When compiled with clang 3.4
and 3.5
using clang++ test.cpp --std=c++11
however, the compilation fails:
test.cpp:8:16: error: static_assert expression is not an integral constant expression
static_assert(arr[0] == arr2[0], "asdf");
^~~~~~~~~~~~~~~~~
test.cpp:8:16: note: non-constexpr function 'operator[]' cannot be used in a constant expression
So my question is, which compiler is "right" in the sense of being compliant with C++11? And, if clang
is correct, then why is std::array's operator[]
not constexpr capable? Isn't that rather one of the things that std::array
was supposed to help resolve?
It looks like clang
is correct, operator [] is not a constexpr in C++11 but is a constexpr in C++14
constexpr const_reference operator[]( size_type pos ) const; (since C++14)
so compiling with -std=c++14
should work though (see it live).
In the C++11 draft standard section 23.3.2.1
Class template array overview has the following for operator []
:
reference operator[](size_type n);
const_reference operator[](size_type n) const;
while the C++14 draft standard has the following:
reference operator[](size_type n);
constexpr const_reference operator[](size_type n) const;
^^^^^^^^^
Update
Draft standard N3485 which came after C++11, contains fixes an enhancements to C++11. It contains a constexpr version of operator []
. If this was part of a defect report then gcc
would be correct and this seems plausible considering clang 3.6.0
also accepts the program in C++11 mode.
Update 2
I found the document that introduced the changes, N3470 and since I can not find any defect reports on this specific issue then this seems like an enhancement and therefore should not be part of C++11.
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