Confusion regarding extern with function definitions in C [duplicate]

Question

Possible Duplicate:
Effects of the `extern` keyword on C functions

Ok, so for a few hours now I've read a lot about what the extern keyword means. And there is one last thing that is bugging me to no end that I cannot find any info about. As far as I understand the extern keyword basically tells the compiler that the variable or function is only a declaration and that it is defined somewhere, so it doesn't have to worry about that, the linker will handle it.

And the warning generated by the compiler (I'm using gcc 4.2.1) when typing this:

extern int var = 10;

supports this. With extern this should be a declaration only so it is not correct.

However, the thing that is confusing me is the absence of a warning or anything when typing this:

extern int func() {return 5;}

This is a definition, and it should generate the same warning, but it does not. The only explanation to this I was able to find here is that the definition overrides the extern keyword. However, following that logic why does it not override it when it is a variable definition? Or does the keyword have special meaning when used with variables?

I would be most grateful if someone explained this to me. Thank you!

Answer 1

The extern keyword indeed has special meaning only when it is used with variables. Using extern with function prototypes is entirely optional:

extern void foo(int bar);

is equivalent to

void foo(int bar);

When you declaring/defining a function, you have two options:

1. Provide only a declaration (i.e. a prototype), or
2. Provide a definition, which also serves as a declaration in the absence of a prototype.

With variables, however, you have three options:

1. Provide only a declaration,
2. Provide a definition with the default initializer: int var; without the = 10 part, or
3. Provide a definition with a specific initializer: int var = 10

Since there are only two options for functions, the compiler can distinguish between then without the use of extern keyword. Any declaration that does not have a static keywords is considered extern by default. Therefore, the extern keyword is ignored with all function declarations or definitions.

With variables, however, the keyword is needed to distinguish between the #1 and the #2. When you use extern, it's #1; when you do not use extern, it's #2. When you try to add extern to #3, it's a warning, because it remains a definition, and the extern is ignored.

All of this is somewhat simplified: you can provide declarations several times in the same compilation unit, and you can provide them at the global scope or at a block scope. For complete details, check section 6.7.9 5 of the C standard.