I have two tables, SystemVariables
and VariableOptions
. SystemVariables
should be self-explanatory, and VariableOptions
contains all of the possible choices for all of the variables.
VariableOptions
has a foreign key, variable_id
, which states which variable it is an option for. SystemVariables
has a foreign key, choice_id
, which states which option is the currently selected one.
I've gotten around the circular relationship using use_alter
on choice_id
, and post_update
on SystemVariables
' choice
relationship. However, I would like to add an extra database constraint that will ensure that choice_id
is valid (i.e. it's referring to an option that is referring back to it).
The logic I need, assuming that sysVar
represents a row in the SystemVariables
table, is basically:
VariableOptions[sysVar.choice_id].variable_id == sysVar.id
But I don't know how to construct this kind of constraint using SQL, declarative, or any other method. If necessary I could just validate this at the application level, but I'd like to have it at the database level if possible. I'm using Postgres 9.1.
Is this possible?
You can implement that without dirty tricks. Just extend the foreign key referencing the chosen option to include variable_id
in addition to choice_id
.
Here is a working demo. Temporary tables, so you can easily play with it:
CREATE TABLE systemvariables (
variable_id int PRIMARY KEY
, choice_id int
, variable text
);
INSERT INTO systemvariables(variable_id, variable) VALUES
(1, 'var1')
, (2, 'var2')
, (3, 'var3')
;
CREATE TABLE variableoptions (
option_id int PRIMARY KEY
, variable_id int REFERENCES systemvariables ON UPDATE CASCADE ON DELETE CASCADE
, option text
, UNIQUE (option_id, variable_id) -- needed for the FK
);
ALTER TABLE systemvariables
ADD CONSTRAINT systemvariables_choice_id_fk
FOREIGN KEY (choice_id, variable_id) REFERENCES variableoptions(option_id, variable_id);
INSERT INTO variableoptions VALUES
(1, 'var1_op1', 1)
, (2, 'var1_op2', 1)
, (3, 'var1_op3', 1)
, (4, 'var2_op1', 2)
, (5, 'var2_op2', 2)
, (6, 'var3_op1', 3)
;
Choosing an associated option is allowed:
UPDATE systemvariables SET choice_id = 2 WHERE variable_id = 1;
UPDATE systemvariables SET choice_id = 5 WHERE variable_id = 2;
UPDATE systemvariables SET choice_id = 6 WHERE variable_id = 3;
But there is no getting out of line:
UPDATE systemvariables SET choice_id = 7 WHERE variable_id = 3;
UPDATE systemvariables SET choice_id = 4 WHERE variable_id = 1;
ERROR: insert or update on table "systemvariables" violates foreign key constraint "systemvariables_choice_id_fk" DETAIL: Key (choice_id,variable_id)=(4,1) is not present in table "variableoptions".
Exactly what you wanted.
NOT NULL
I think I found a better solution in this later answer:
Addressing the @ypercube's question in the comments, to avoid entries with unknown association make all key columns NOT NULL
, including foreign keys.
The circular dependency would normally make that impossible. It's the classical chicken-egg problem: one of both has to be there first to spawn the other. But nature found a way around it, and so did Postgres: deferrable foreign key constraints.
CREATE TABLE systemvariables (
variable_id int PRIMARY KEY
, variable text
, choice_id int NOT NULL
);
CREATE TABLE variableoptions (
option_id int PRIMARY KEY
, option text
, variable_id int NOT NULL REFERENCES systemvariables
ON UPDATE CASCADE ON DELETE CASCADE DEFERRABLE INITIALLY DEFERRED
, UNIQUE (option_id, variable_id) -- needed for the foreign key
);
ALTER TABLE systemvariables
ADD CONSTRAINT systemvariables_choice_id_fk FOREIGN KEY (choice_id, variable_id)
REFERENCES variableoptions(option_id, variable_id) DEFERRABLE INITIALLY DEFERRED; -- no CASCADING here!
New variables and associated options have to be inserted in the same transaction:
BEGIN;
INSERT INTO systemvariables (variable_id, variable, choice_id)
VALUES
(1, 'var1', 2)
, (2, 'var2', 5)
, (3, 'var3', 6);
INSERT INTO variableoptions (option_id, option, variable_id)
VALUES
(1, 'var1_op1', 1)
, (2, 'var1_op2', 1)
, (3, 'var1_op3', 1)
, (4, 'var2_op1', 2)
, (5, 'var2_op2', 2)
, (6, 'var3_op1', 3);
END;
The NOT NULL
constraint cannot be deferred, it is enforced immediately. But the foreign key constraint can, because we defined it that way. It is checked at the end of the transaction, which avoids the chicken-egg problem.
In this edited scenario, both foreign keys are deferred. You can enter variables and options in arbitrary sequence.
You can even make it work with plain non-deferrable FK constraint if you enter related entries in both table in one statement using CTEs as detailed in the linked answer.
You may have noticed that the first foreign key constraint has no CASCADE
modifier. (It wouldn't make sense to allow changes to variableoptions.variable_id
to cascade back.
On the other hand, the second foreign key has a CASCADE
modifier and is defined DEFERRABLE
nonetheless. This carries some limitations. The manual:
Referential actions other than the
NO ACTION
check cannot be deferred, even if the constraint is declared deferrable.
NO ACTION
is the default.
So, referential integrity checks on INSERT
are deferred, but the declared cascading actions on DELETE
and UPDATE
are not. The following is not permitted in PostgreSQL 9.0 or later because constraints are enforced after each statement:
UPDATE option SET var_id = 4 WHERE var_id = 5;
DELETE FROM var WHERE var_id = 5;
Details:
EDIT: The 0.7.4 release of SQLAlchemy (released the same day I started asking about this issue, 7/12/'11!), contains a new autoincrement
value for primary keys that are also part of foreign keys, ignore_fk
. The documentation has also been expanded to include a good example of what I was originally trying to accomplish.
All is now explained well here.
If you want to see the code I came up with before the above release, check the revision history of this answer.
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