How would I compare only the year-month-day components of 2 NSDates
?
So here's how you'd do it:
NSCalendar *calendar = [NSCalendar currentCalendar];
NSInteger desiredComponents = (NSDayCalendarUnit | NSMonthCalendarUnit | NSYearCalendarUnit);
NSDate *firstDate = ...; // one date
NSDate *secondDate = ...; // the other date
NSDateComponents *firstComponents = [calendar components:desiredComponents fromDate:firstDate];
NSDateComponents *secondComponents = [calendar components:desiredComponents fromDate:secondDate];
NSDate *truncatedFirst = [calendar dateFromComponents:firstComponents];
NSDate *truncatedSecond = [calendar dateFromComponents:secondComponents];
NSComparisonResult result = [truncatedFirst compare:truncatedSecond];
if (result == NSOrderedAscending) {
//firstDate is before secondDate
} else if (result == NSOrderedDescending) {
//firstDate is after secondDate
} else {
//firstDate is the same day/month/year as secondDate
}
Basically, we take the two dates, chop off their hours-minutes-seconds bits, and the turn them back into dates. We then compare those dates (which no longer have a time component; only a date component) and see how they compare to eachother.
WARNING: typed in a browser and not compiled. Caveat implementor
Check out this topic NSDate get year/month/day
Once you pull out the day/month/year, you can compare them as integers.
If you don't like that method
Instead, you could try this..
NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];
[dateFormatter setDateFormat:@"yyyy"];
int year = [[dateFormatter stringFromDate:[NSDate date]] intValue];
[dateFormatter setDateFormat:@"MM"];
int month = [[dateFormatter stringFromDate:[NSDate date]] intValue];
[dateFormatter setDateFormat:@"dd"];
int day = [[dateFormatter stringFromDate:[NSDate date]] intValue];
And another way...
NSDateComponents *dateComp = [calendar components:unitFlags fromDate:date];
NSInteger year = [dateComp year];
NSInteger month = [dateComp month];
NSInteger day = [dateComp day];
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