Comparing and Concatenating Tuples in Python

Question

I have a python tuple whose elements are actually sentences. I want to compare the first letters of each element and if they are lowercase, I join it to the previous element. And if they aren't I just join the first element. For instance if I have:

tuple1 = ('Traditionally, companies have been communicating', 'with consumers through traditional or old media.', 'The rapid changes in the cyber world.', 'This is another sentence', 'which is incomplete.')

My result should be:

tuple1 = ('Traditionally, companies have been communicating with consumers through traditional or old media.', 'The rapid changes in the cyber world.', 'This is another sentence which is incomplete.')

This is my working code:

i=0 
while i<(len(tuple1)-1):
   if tuple1[i+1][0].islower():
       tuple1[i] + " " + tuple[i+1]
   i+=1

How can I achieve this? Thanks

Answer 1

You can use itertools.groupby:

import itertools  
tuple1 = ('Traditionally, companies have been communicating', 'with consumers through traditional or old media.', 'The rapid changes in the cyber world.', 'This is another sentence', 'which is incomplete.')
new_data = tuple(' '.join(i[-1] for i in b) for _, b in itertools.groupby(enumerate(tuple1), key=lambda x:x[-1][0].islower() or tuple1[x[0]+1][0].islower() if x[0]+1 < len(tuple1) else True))

Output:

('Traditionally, companies have been communicating with consumers through traditional or old media.', 'The rapid changes in the cyber world.', 'This is another sentence which is incomplete.')

Answer 2

Hope this does what you are looking for. I did it without using any external modules.

b = ('Traditionally, companies have been communicating', 'with consumers through traditional or old media.', 'The rapid changes in the cyber world.')
i=0
a=[]
num=0
for element in b:
    print(element)
    if element[i][0].islower():
        a[-1]=a[-1]+element
    else:
        a.append(element)
        num=num+1
print(a)