Compare two NSDates for same date/time [duplicate]

Question

Is date1 == date2 not a valid way to compare? If not, what is the correct alternative?

Here's my code:

- (NSDate*) dateWithNoTime {
    unsigned int flags = NSYearCalendarUnit | NSMonthCalendarUnit | NSDayCalendarUnit;
    NSCalendar* calendar = [NSCalendar currentCalendar];
    NSDateComponents* components = [calendar components:flags fromDate:self];
    NSDate* dateOnly = [calendar dateFromComponents:components];
    return dateOnly;
}

- (BOOL) sameDayAsDate:(NSDate*)dateToCompare {
    NSDate *date1 = [self dateWithNoTime];
    NSDate *date2 = [dateToCompare dateWithNoTime];
    return date1 == date2;       // HERE IS WHERE THINGS SEEM TO FAIL

}

Answer 1

You're comparing two pointer values. You need to use the NSDate comparison method like:

return ([date1 compare:date2] == NSOrderedSame);

Answer 2

As in the C language (of which Objective-C is a superset), the == (equality) operator compares two pointer values to see if they are equivalent (i.e. if two variables hold the same object). While this works in comparing primitive values (ints, chars, bools), it does not work on Objective-C objects, which might be equal in content, but differ in memory location (which is what the equality operator compares).

To check if two objects are equal, NSObject offers an -isEqual: method which you can use as a general statement (e.g. [date1 isEqual:date2]), and some classes choose to offer a more specific comparison method, such as -isEqualToDate: used to compare NSDates, or -isEqualToString: used to compare NSStrings. These methods cannot be used to compare primitive types (ints, for instance) because those are not objects, but will work on almost all objects.