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Compact Framework - how do I dynamically create type with no default constructor?

I'm using the .NET CF 3.5. The type I want to create does not have a default constructor so I want to pass a string to an overloaded constructor. How do I do this?

Code:

Assembly a = Assembly.LoadFrom("my.dll");
Type t = a.GetType("type info here");
// All ok so far, assembly loads and I can get my type

string s = "Pass me to the constructor of Type t";
MyObj o = Activator.CreateInstance(t); // throws MissMethodException
like image 678
Brian Lyttle Avatar asked Aug 27 '08 03:08

Brian Lyttle


2 Answers

MyObj o = null;
Assembly a = Assembly.LoadFrom("my.dll");
Type t = a.GetType("type info here");

ConstructorInfo ctor = t.GetConstructor(new Type[] { typeof(string) });
if(ctor != null)
   o = ctor.Invoke(new object[] { s });
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Chris Karcher Avatar answered Nov 07 '22 07:11

Chris Karcher


Ok, here's a funky helper method to give you a flexible way to activate a type given an array of parameters:

static object GetInstanceFromParameters(Assembly a, string typeName, params object[] pars) 
{
    var t = a.GetType(typeName);

    var c = t.GetConstructor(pars.Select(p => p.GetType()).ToArray());
    if (c == null) return null;

    return c.Invoke(pars);
}

And you call it like this:

Foo f = GetInstanceFromParameters(a, "SmartDeviceProject1.Foo", "hello", 17) as Foo;

So you pass the assembly and the name of the type as the first two parameters, and then all the constructor's parameters in order.

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Matt Hamilton Avatar answered Nov 07 '22 07:11

Matt Hamilton