Firs of all excuse me for my bad english.
I'm trying to generate combinations of symbols taking them from str: TStringList (Xn, Yn) where X is the position of the char in the new word and Y is the variable for the position.
For example lets say my StringList have
str[0]: '013456789'
str[1]: 'abcdef'
str[2]: '5421'
In this case I will expact 216 words (length(str[0]) * length(str[1]) * length(str[2])) The result will be like:
str[0][1]+ str[1][1]+ str[2][1] -> 0a5
str[0][1]+ str[1][1]+ str[2][2] -> 0a4
str[0][1]+ str[1][1]+ str[2][3] -> 0a2
str[0][1]+ str[1][1]+ str[2][4] -> 0a1
str[0][1]+ str[1][2]+ str[2][1] -> 0b5
str[0][1]+ str[1][2]+ str[2][2] -> 0b4
str[0][1]+ str[1][2]+ str[2][3] -> 0b2
str[0][1]+ str[1][2]+ str[2][4] -> 0b1
str[0][1]+ str[1][3]+ str[2][1] -> 0c5
str[0][1]+ str[1][3]+ str[2][2] -> 0c4
str[0][1]+ str[1][3]+ str[2][3] -> 0c2
str[0][1]+ str[1][3]+ str[2][4] -> 0c1
and so on untill
str[0][10]+ str[1][6]+ str[2][3] -> 9f2
str[0][10]+ str[1][6]+ str[2][4] -> 9f1
Now I'm comfused how to make the "FOR" loops to make cicles for every possible word.
Best regards Martin
This can be done with recursion.
procedure Recurse(startIx,stopIx: Integer; prefix: String; const aList: TStringList);
var
ch : Char;
begin
if (startIx > stopIx) then begin
WriteLn(prefix);
end
else
begin
for ch in aList[startIx] do begin
Recurse( startIx+1,stopIx,prefix + ch,aList);
end;
end;
end;
Recurse(0,str.Count-1,'',str);
Recursion may seem like magic at first, but is a very effective way to solve this kind of combinatorics.
The solution to this problem is a Cartesian product
.
Should you have an older Delphi version, iterate the character like this:
procedure Recurse(startIx,stopIx: Integer; prefix: String; const aList: TStringList);
var
i : Integer;
begin
if (startIx > stopIx) then begin
WriteLn(prefix);
end
else
begin
for i := 1 to Length(aList[startIx]) do begin
Recurse( startIx+1,stopIx,prefix + aList[startIx][i],aList);
end;
end;
end;
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