How can I get (using the std::chrono library) the difference between two points in time in milliseconds?
I could do that using this:
std::chrono::time_point<std::chrono::system_clock> now = std::chrono::system_clock::now(); std::chrono::time_point<std::chrono::system_clock> foo = now + std::chrono::milliseconds(100); std::chrono::duration<float> difference = foo - now; const int milliseconds = difference.count() * 1000;
How can I get this time in milliseconds, so I can use the duration as a unsigned int, and not a float and then multiply by 1000?
Class template std::chrono::duration represents a time interval. It consists of a count of ticks of type Rep and a tick period, where the tick period is a compile-time rational fraction representing the time in seconds from one tick to the next. The only data stored in a duration is a tick count of type Rep .
std::chrono::secondsInstantiation of duration to represent seconds.
std::chrono::duration
has two template parameters, the second being exactly the unit of measure. You can invoke std::chrono::duration_cast
to cast from one duration type to another. Also, there is a predefined duration type for milliseconds: std::chrono::milliseconds
. Composing this together:
auto milliseconds = std::chrono::duration_cast<std::chrono::milliseconds>(foo - now);
To get the actual number of milliseconds, use duration::count
:
auto ms = milliseconds.count();
Its return type is duration::rep
, which for standard duration types like std::chrono::milliseconds
is a signed integer of unspecified size.
chrono::duration_cast<chrono::milliseconds>(end_time - start_time).count()
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With