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Checking if a point is inside a polygon

I have a class describing a Point (has 2 coordinates x and y) and a class describing a Polygon which has a list of Points which correspond to corners (self.corners) I need to check if a Point is in a Polygon

Here is the function that is supposed to check if the Point is in the Polygon. I am using the Ray Casting Method

def in_me(self, point):
        result = False
        n = len(self.corners)
        p1x = int(self.corners[0].x)
        p1y = int(self.corners[0].y)
        for i in range(n+1):
            p2x = int(self.corners[i % n].x)
            p2y = int(self.corners[i % n].y)
            if point.y > min(p1y,p2y):
                if point.x <= max(p1x,p2x):
                    if p1y != p2y:
                        xinters = (point.y-p1y)*(p2x-p1x)/(p2y-p1y)+p1x
                        print xinters
                    if p1x == p2x or point.x <= xinters:
                        result = not result
            p1x,p1y = p2x,p2y
         return result

I run a test with following shape and point:

PG1 = (0,0), (0,2), (2,2), (2,0)
point = (1,1)

The script happily returns False even though the point it within the line. I am unable to find the mistake

like image 516
Helena Avatar asked May 18 '13 14:05

Helena


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2 Answers

I would suggest using the Path class from matplotlib

import matplotlib.path as mplPath
import numpy as np

poly = [190, 50, 500, 310]
bbPath = mplPath.Path(np.array([[poly[0], poly[1]],
                     [poly[1], poly[2]],
                     [poly[2], poly[3]],
                     [poly[3], poly[0]]]))

bbPath.contains_point((200, 100))

(There is also a contains_points function if you want to test for multiple points)

like image 117
P.R. Avatar answered Oct 17 '22 11:10

P.R.


I'd like to suggest some other changes there:

def contains(self, point):
    if not self.corners:
        return False

    def lines():
        p0 = self.corners[-1]
        for p1 in self.corners:
            yield p0, p1
            p0 = p1

    for p1, p2 in lines():
        ... # perform actual checks here

Notes:

  • A polygon with 5 corners also has 5 bounding lines, not 6, your loop is one off.
  • Using a separate generator expression makes clear that you are checking each line in turn.
  • Checking for an empty number of lines was added. However, how to treat zero-length lines and polygons with a single corner is still open.
  • I'd also consider making the lines() function a normal member instead of a nested utility.
  • Instead of the many nested if structures, you could also check for the inverse and then continue or use and.
like image 35
Ulrich Eckhardt Avatar answered Oct 17 '22 10:10

Ulrich Eckhardt