Check if integer is multiple of 8

Question

Hi i'm new to c++ so i'm not sure if this is a really silly question. Basically i'm using a c++ custom action project to interact with my MSI installer. I get a property that my user will have entered, it is an integer. I need to ensure that this is a multiple of 8 and i'm not sure how to go about this. Obviously if it can be divided by 8 it is a multiple but I am not sure how to capture if there is a remainder. Any help would be appreciated or even point me in the right direction. Thanks

Answer 1

Use the "modulo" operator, which gives the remainder from division:

if (n % 8 == 0) {
    // n is a multiple of 8
}

Answer 2

Use the "modulo" or "integer remainder operator" %:

int a = ....;
if (a % 8 == 0 ) {
  // a is amultiple of 8
}

Answer 3

use operator %

if ( num % 8 == 0 )
{
    // num is multple of 8
}

Answer 4

Checking only the last 3 digits of a number does the job.
Even if you are given a huge number in the form of a string where the % operating is not useful you can check if only the last 3 digits are divisible by 8 then the whole number is divisible by 8.