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I have a problem with this code:
if (90 >>= angle =<< 180)
The error explanation is:
The left-hand side of an assignment must be a variable.
I understand what this means but how do I turn the above code into correct code?
859
To check if a number is between two numbers: Use the && (and) operator to chain two conditions. In the first condition check that the number is greater than the lower range and in the second, that the number is lower than the higher range.
For example, you need to check if value in cell B2 is between values in cell A2 and A3. Please apply the following formula to achieve it. 1. Select a blank cell which you need to display the result, enter formula =IF(AND(B2>A2,B2<A3),"Yes","No") into the Formula Bar and then press the Enter key.
between() is a static method of the Range which is used to obtain an instance of Range with the specified minimum and maximum value. The specified minimum and maximum values are inclusive in nature. The method optionally takes in a custom Comparator for custom comparison logic.
If x is in range, then it must be greater than or equal to low, i.e., (x-low) >= 0. And must be smaller than or equal to high i.e., (high – x) <= 0. So if result of the multiplication is less than or equal to 0, then x is in range.
I see some errors in your code.
Your probably meant the mathematical term
90 <= angle <= 180, meaning angle in range 90-180.
if (angle >= 90 && angle <= 180) {
// do action
}
You can use apache Range API. https://commons.apache.org/proper/commons-lang/apidocs/org/apache/commons/lang3/Range.html
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