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Check if a textbox value is a string or a number in javascript

Tags:

javascript

Basically I have the following code:

<input type="text" value="123" id="txtbox">
<script>
var myVar = document.getElementById('txtbox').value;

if (myVar.substring) {
alert('string');
} else{
alert('number');
}
</script>

No matter what value you put in the textbox, it will always alert string. Is there a way that if you put a number in the textbox it will alert number instead of string? Thank you.

like image 205
wobsoriano Avatar asked May 04 '15 14:05

wobsoriano


2 Answers

value on input elements is always a string. It might be a string of digits.

If you want to know whether that string only contains valid numbers, you have to parse it (and decide what you consider a valid number, and allow for that).

For instance, you'll get people telling you to use parseInt(myVar) or the unary + (+myVar) or isNaN(myVar) (which does what the unary + does) or Number(myVar) (same), but:

  1. parseInt only parses the beginning of the string, parseInt("345foo") is 345

  2. parseInt is, of course, only for whole numbers; you'd want parseFloat for numbers with fractional portions

  3. All of those will fail to understand thousands separators

  4. All of those will fail to understand a decimal separator that isn't . (e.g., in many locales it's , or sometimes even a space)

  5. +myVar and Number(myVar) and isNaN(myVar) and such will treat an empty string as 0

...that kind of thing. So you have to do some prep on the string according to what input you want to accept.

Once you've decide what format(s) to handle, there are a dozen questions with answers here about doing the actual parsing:

  • How do I Convert a String into an Integer in JavaScript? (note that's integer-specific)
  • What's the fastest way to convert String to Number in JavaScript?
like image 82
T.J. Crowder Avatar answered Sep 22 '22 10:09

T.J. Crowder


is isNaN (literally "is Not a Number"):

var myVar = document.getElementById('txtbox').value;

var myNum = +myVar;//as suggested by T.J. 
if (isNaN(myNum)) {
   alert('string');
} else{
   alert('number');
}
like image 24
KJ Price Avatar answered Sep 18 '22 10:09

KJ Price