Check if a string is blank or doesn't exist in Scala

Question

I have an Option[String].

I want to check if there is a string exists and if it's exists its not blank.

def isBlank( input : Option[String]) : Boolean = 
{ 
     input.isEmpty || 
     input.filter(_.trim.length > 0).isEmpty 
}

Is there is a better way of doing this in Scala ?

Answer 1

What you should do is check using exists. Like so:

myOption.exists(_.trim.nonEmpty)

which will return True if and only if the Option[String] is not None and not empty.

Answer 2

An approach based in pattern matching,

def isBlank( input : Option[String]) : Boolean = 
  input match {
    case None    => true
    case Some(s) => s.trim.isEmpty
  }

Answer 3

exists (Accepted solution) will work when input has at least one element in it, that is Some("") but not when it's None.

exists checks if at least one element(x) applies to function.

eg.

scala> List[String]("apple", "").exists(_.isEmpty)
res21: Boolean = true

//if theres no element then obviously returns false
scala> List[String]().exists(_.isEmpty)
res30: Boolean = false

Same happens with Option.empty, as theres no element in it,

scala> Option.empty[String].exists(_.isEmpty)
res33: Boolean = false

So forall is what makes sure the the function applies all the elements.

scala> def isEmpty(sOpt: Option[String]) = sOpt.forall(_.trim.isEmpty)
isEmpty: (sOpt: Option[String])Boolean

scala> isEmpty(Some(""))
res10: Boolean = true

scala> isEmpty(Some("non-empty"))
res11: Boolean = false

scala> isEmpty(Option(null))
res12: Boolean = true

The gross way is to filter nonEmpty string, then check option.isEmpty.

scala> def isEmpty(sOpt: Option[String]) = sOpt.filter(_.trim.nonEmpty).isEmpty
isEmpty: (sOpt: Option[String])Boolean

scala> isEmpty(None)
res20: Boolean = true

scala> isEmpty(Some(""))
res21: Boolean = true

Answer 4

This should work as well since filter of an empty Option results in an empty Option

def isBlank( input : Option[String]) : Boolean =  
   input.filter(_.trim.length > 0).isEmpty