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The string of example is:
abcdefghijklmno
If I give in input:
abc FALSE #at least 4 characters.
abcd TRUE
cdefg FALSE #because the match must start from the first character.
abcde TRUE
abcdeghi FALSE #because the characters must be contained consecutively.
abcdefgh TRUE
abcdefghi TRUE
abcdefghijklmno TRUE
abcdefghijklmnop FALSE #because it exceeds the example string.
i have tried:
set -- abc
i=1
[[ abcdefghijklmno == ${!i}* ]]
echo $?
but echo "$?" returns 0 also with 3, 2, 1 or 0 characters.
This other code is obviously wrong but it is to communicate what I would like to do:
set -- abc
i=1
[[ abcdefghijklmno == ${!i}{4}* ]]
echo $?
EDIT:
The solution that suits me is the following:
set -- abc
i=1
[[ abcdefghijklmno == ${!i}* && $(expr length "${!i}") -ge 4 ]]
echo $?
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You can use contains(), indexOf() and lastIndexOf() method to check if one String contains another String in Java or not. If a String contains another String then it's known as a substring. The indexOf() method accepts a String and returns the starting position of the string if it exists, otherwise, it will return -1.
You can use the substr function like this: echo substr($myStr, 0, 5); The second argument to substr is from what position what you want to start and third arguments is for how many characters you want to return.
Using Python's "in" operator The simplest and fastest way to check whether a string contains a substring or not in Python is the "in" operator . This operator returns true if the string contains the characters, otherwise, it returns false .
Use the String. substring() method to get the first two characters of a string, e.g. const first2 = str. substring(0, 2); . The substring method will return a new string containing the first two characters of the original string.
You may us this awk:
awk -v s='abcdefghijklmno' '{
print $0, (length($1) > 3 && index(s, $1) == 1 ? "TRUE" : "FALSE")}' file | column -t
abc FALSE
abcd TRUE
cdefg FALSE
abcde TRUE
abcdeghi FALSE
abcdefgh TRUE
abcdefghi TRUE
abcdefghijklmno TRUE
abcdefghijklmnop FALSE
Explained:
column command has been used for tabular output only.length($1) > 3 && index(s, $1) == 1: Check condition that length of first field is greater than 3 and $1 is found from first position in the given string s.Alternatively, we can also use a regex to check presence of $1 from start:
awk -v s='abcdefghijklmno' '{
print $0, (length($1) > 3 && s ~ "^" $1 ? "TRUE" : "FALSE")
}' file
The index function of Perl seems adapted: given two strings, it returns the index at which the second one occurs in the first one, or -1 if it does not occur. What you want to do is thus to check if the second string appears in the first one, at the index 0. Then, you can use the length function to make sure that the second string is more than 4 characters long
For instance,
length("abc") >= 4 && index("abcdefghijklmno", "abc") == 0 # true
length("cdefg") >= 4 && index("abcdefghijklmno", "cdefg") == 0 # false
length("abcdefghijklmno") >= 4 && index("abcdefghijklmno", "abcdefghijklmno") == 0 # true
To use it in a one-liner, one way is to provide both strings on the command line. For instance:
perl -e 'print length($ARGV[1]) >= 4 && index($ARGV[0], $ARGV[1]) == 0 ? "TRUE" : "FALSE"' abcdefghijklmno abc
Alternatively, you can sacrifice readability for conciseness by using a regular expression:
perl -e 'print $ARGV[0] =~ /^\Q$ARGV[1]\E(?<=.{4})/ ? "TRUE" : "FALSE"' abcdefghijklmno abcde
Where the regex checks if the first string starts with the second one (/^\Q$ARGV[1]\E), and that the second one is 4 characters long or more ((?<=.{4}); see perlre#lookaround-assertions).
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