Menu
So I'm working through a few of the exercises in "Scala for the Impatient" and one of them is:
Write a for loop for computing the product of the Unicode codes of all letters in a string. For example, the product of the characters in "Hello" is 9415087488 L.
The next problem is to do the same, but without a for loop - it hints that we should check StringOps in Scaladoc.
I checked the RichChar and StringOps section in Scaladoc, and perhaps I'm misreading or looking in the wrong places, but I can't find anything that gets me to match their output. I've thus far tried:
scala> x.foldLeft(1)(_ * _.toInt) res0: Int = 825152896 scala> x.foldLeft(1)(_ * _.getNumericValue) res5: Int = 2518992 scala> x.foldLeft(1)(_ * _.intValue()) res6: Int = 825152896 scala> var x = 1 x: Int = 1 scala> for (c <- "Hello") x *= c.toInt scala> x res12: Int = 825152896 Which does not match their output.
How do I do this, in both the for and non-for way?
Thanks!
809
A string literal is a sequence of characters in double quotes. The characters are either printable unicode character or are described by escape sequences. If the string literal contains a double quote character, it must be escaped, i.e. "\"" . The value of a string literal is an instance of class String .
Scala Char |(x: Char) method with exampleThe |(x: Char) method is utilized to find the bit-wise OR of the stated character value and given 'x' in the argument list. Return Type: It returns the bit-wise OR of the stated character value and given 'x'.
An escape value is a backslash with a character that will escape that character to execute a certain functionality. We can use these in character and string literals. We have the following escape values in Scala: Escape Sequences. Unicode.
Unicode is an international standard of character encoding which has the capability of representing a majority of written languages all over the globe. Unicode uses hexadecimal to represent a character. Unicode is a 16-bit character encoding system. The lowest value is \u0000 and the highest value is \uFFFF.
When you do x.foldLeft(1)(_ * _.toInt), the result type will be inference to an Int, but 9415087488 is too large for an Int to store it.
So you need to tell Scala using Long to store it.
scala> val x = "Hello" x: java.lang.String = Hello scala> x.foldLeft(1L)(_ * _.toInt) res1: Long = 9415087488 scala> var x: Long = 1 x: Long = 1 scala> for (c <- "Hello") x *= c.toInt scala> x res7: Long = 9415087488 If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With
