index = [0, 2, 5]
s = "I am like stackoverflow-python"
for i in index:
s = s[i].upper()
print(s)
IndexError: string index out of range
I understand that in the first iteration the string, s
, become just the first character, an uppercase "I" in this particular case. But, I have tried to do it without the "s = " , using swapchcase()
instead, but it's not working.
Basically, I'm trying to print the s
string with the index letters as uppercase using Python 3.X
The toLowerCase() method converts a string to lower case letters. Note: The toUpperCase() method converts a string to upper case letters.
In Python, upper() is a built-in method used for string handling. The upper() method returns the uppercased string from the given string. It converts all lowercase characters to uppercase. If no lowercase characters exist, it returns the original string.
Strings are immutable in Python, so you need to create a new string object. One way to do it:
indices = set([0, 7, 12, 25])
s = "i like stackoverflow and python"
print("".join(c.upper() if i in indices else c for i, c in enumerate(s)))
printing
I like StackOverflow and Python
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With