Select the element and click the gear icon to open the Properties panel. Go to the Advanced tab. Scroll down and toggle the Hide Field option to “On”.
The disabled boolean argument, when set to True , disables a form field using the disabled HTML attribute so that it won't be editable by users. Even if a user tampers with the field's value submitted to the server, it will be ignored in favor of the value from the form's initial data.
The <input type="hidden"> defines a hidden input field. A hidden field let web developers include data that cannot be seen or modified by users when a form is submitted. A hidden field often stores what database record that needs to be updated when the form is submitted.
If you want to drop the data completely, you need to create a Django migration (using ./manage.py makemigrations preferably) that will remove those columns from the database.
This may also be useful: {{ form.field.as_hidden }}
If you have a custom template and view you may exclude the field and use {{ modelform.instance.field }}
to get the value.
also you may prefer to use in the view:
form.fields['field_name'].widget = forms.HiddenInput()
but I'm not sure it will protect save method on post.
Hope it helps.
an option that worked for me, define the field in the original form as:
forms.CharField(widget = forms.HiddenInput(), required = False)
then when you override it in the new Class it will keep it's place.
Firstly, if you don't want the user to modify the data, then it seems cleaner to simply exclude the field. Including it as a hidden field just adds more data to send over the wire and invites a malicious user to modify it when you don't want them to. If you do have a good reason to include the field but hide it, you can pass a keyword arg to the modelform's constructor. Something like this perhaps:
class MyModelForm(forms.ModelForm):
class Meta:
model = MyModel
def __init__(self, *args, **kwargs):
from django.forms.widgets import HiddenInput
hide_condition = kwargs.pop('hide_condition',None)
super(MyModelForm, self).__init__(*args, **kwargs)
if hide_condition:
self.fields['fieldname'].widget = HiddenInput()
# or alternately: del self.fields['fieldname'] to remove it from the form altogether.
Then in your view:
form = MyModelForm(hide_condition=True)
I prefer this approach to modifying the modelform's internals in the view, but it's a matter of taste.
For normal form you can do
class MyModelForm(forms.ModelForm):
slug = forms.CharField(widget=forms.HiddenInput())
If you have model form you can do the following
class MyModelForm(forms.ModelForm):
class Meta:
model = TagStatus
fields = ('slug', 'ext')
widgets = {'slug': forms.HiddenInput()}
You can also override __init__
method
class Myform(forms.Form):
def __init__(self, *args, **kwargs):
super(Myform, self).__init__(*args, **kwargs)
self.fields['slug'].widget = forms.HiddenInput()
If you want the field to always be hidden, use the following:
class MyForm(forms.Form):
hidden_input = forms.CharField(widget=forms.HiddenInput(), initial="value")
If you want the field to be conditionally hidden, you can do the following:
form = MyForm()
if condition:
form.fields["field_name"].widget = forms.HiddenInput()
form.fields["field_name"].initial = "value"
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