Casting type inside Optional

Question

I have the following:

class Foo implements Inter {
    void doSomething();
}

Optional<Inter> getPossible() {
    Optional<Foo> possible = ...;
    possible.ifPresent(Foo::doSomething);
    return possible.map(f -> f);
}

getPossible needs to return an Optional<Inter> because it's overriding a superclass's implementation.

That map at the end of the method is purely to convert the type. Is there a more elegant option?

Answer 1

To make clear that you only need casting, you can use Class::cast with .map:

class Foo implements Inter {
    void doSomething();
}

Optional<Inter> getPossible() {
    Optional<Foo> possible = ...;
    possible.ifPresent(Foo::doSomething);
    return possible.map(Inter.class::cast);
}

Answer 2

Return a Optional<? extends Inter> instead of an Optional<Inter>.