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Cast Boxed Object back to Original Type

I expect there's one of two answers to this, either impossible or extremely simple and I've overlooked the obvious Google query.

The underlying issue is that I have a generic object being passed in via an EventHandler that boxes the object and obfuscates the true type; only at runtime do I know what the object is.

Admittedly the dynamic keyword can get around the issue, but I'd like to not lose IntelliSense and everything if I can avoid it. Plus, it doesn't solve not knowing what each of the properties of the generic object are without massive amounts of reflection.

EDIT: The idea is to be able to determine the true type of the an object in a method parameter, and then cast that object as it's true type without knowing it in advance. This is but a simplified example. Boxed may have been the wrong term.

An example:

public class Program
{
    static void Main(string[] args)
    {
        var container = new Container<Containee>(
            new Containee
            {
                Property1 = Guid.NewGuid(),
                Property2 = "I'm a property!",
                Property3 = DateTime.Now
            }
        );

        var boxed = (object)container;

        var originalType = boxed.GetType();

        // DOES NOT COMPILE: would like an operation like this
        // EDIT: Request for more detail
        var actualType = boxed as originalType;
        actualType.Entity.Property2 = "But I like this better.";
    }
}

public class Containee
{
    public Guid Property1 { get; set; } 
    public string Property2 { get; set; }
    public DateTime Property3 { get; set; }
}

public class Container<T>
{
    public Container(T entity)
    {
        Entity = entity;
    }

    public T Entity { get; internal set; }
}

Clearly that won't compile, as there's not really a way to cast as a variable. However, I'm hoping there's a way to get a reference to the actual object and type, or at least, a way to dynamically re-create the type.

I expect there's something simple I'm overlooking, or a better way to get around it in general. The point is to be able to wrap any object in the container, and figure out later what it was.

like image 592
falquan Avatar asked Jun 10 '11 01:06

falquan


2 Answers

You could use dynamic:

dynamic actualType = boxed;
actualType.Entity.Property2 = "But I like this better.";

This should compile and work.

like image 184
Alex Aza Avatar answered Oct 13 '22 01:10

Alex Aza


The idea is to be able to determine the true type of the an object in a method parameter

That's easy enough (and you're already doing it).

Type actualType = param.GetType();

That will get you the actual concrete type of the object

and then cast that object as it's true type

This is where things come off the rails a bit. The casting operator in C# (usage of which is what people refer to as "casting") can do two things:

  1. Use type-specific explicit conversions to create a new object by applying the conversion to the existing object (note that this is a new reference that is created; the original object's type is never changed)
  2. Allow the developer to reference an object as a type that is at a different level in its inheritance hierarchy than is currently provided (or an interface that is implemented on a type that is lower in the hierarchy than is currently referenced)

In your case, the first option is right out; the casting operator, like all operators, is not polymorphic. That is, an operator is only applied if it is defined on the type that is being referenced, not the object that's being referenced. If you'd like further clarification on this, let me know, but I don't think it's germane to your question so I'm not going to go into it further unless asked.

The second option is the only option that could realistically apply to you, but consider the only two reasons you would want to do this:

  1. So that you can refer to the object as a specific concrete type that is at a lower level than is currently provided (in your case, your object is an object, so that's pretty much as high as it goes)
  2. So that you can refer to an object as a type that is higher in the hierarchy so that you can bypass hidden (but not overridden) members.

(The vast majority of casts are for reason #1)

The reason you would want to use either of those options is so that you can have a strongly-typed object and use the various members defined on that type. But all of these things only apply to types that you know when you're writing the code. It doesn't make sense to cast to a type that is unknown at compile time, as casting doesn't do anything to the actual object (it is, and shall remain, its true type; the only thing that changes is the type of the variable by which you reference the object).

If you can provide a further fleshed-out example of what you're actually trying to do (complete with code as you'd either like or expect it to work), I might be able to provide something modeled a little closer to what you want, but as it's described this is as specific as I can get.

like image 33
Adam Robinson Avatar answered Oct 13 '22 01:10

Adam Robinson