I'm writing an application that leverages jsvc
to start up a Java service as a daemon. I need to use something like jsvc
because my application utilizes ports under 1024 and yet I'd really like to not run it as root so that created files are owned by another user. I'd also like to keep dependencies and configuration to a minimum so that all the client needs is a JVM and the jsvc
binary installed.
However, it seems that jsvc
has one major catch; it can't detect the home folder of Java on a given Unix operating system, which is quite frustrating:
$ ./startup.sh
Cannot locate Java home
I have been able to work around the issue on Ubuntu at least by manually setting the JVM home directory:
jsvc ... -home /usr/lib/jvm/default-java/ ...
Is there any way to determine the Java home directory dynamically from a Bash script so I can make this work across most Unixes/Linuxes? I'd be able to sleep much better at night doing something like:
JAVA_HOME="$( ... )"
jsvc ... -home "$JAVA_HOME" ...
...rather than hard-coding for each individual operating system. Is there a way that, given a java
binary, I can find the home directory of its JVM/JRE?
Not sure if this works across *nixes, but found this solution:
JAVA_HOME="$( readlink -f "$( which java )" | sed "s:bin/.*$::" )"
I've tested it on Ubuntu and it works, however it does not work for OSX.
My solution was compiling the native linux source as the main jsvc page says in http://commons.apache.org/proper/commons-daemon//jsvc.html
Here is my step by step procedure
Download www.fightrice.com/mirrors/apache/commons/daemon/source/commons-daemon-1.0.13-src.tar.gz
Once you extract the file then go to ...../commons-daemon-1.0.13-src/src/native/unix
in terminal as a root do the following:
$ support/buildconf.sh
$ ./configure --with-java=/usr/lib/jvm/default-java
$ make
test generated jsvc binary app
$ ./jsvc -help
It works! cleanly.
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