Can we declare a structure element of variable length?
The condition is as follows:
typedef struct
{
uint8_t No_Of_Employees;
uint8_t Employee_Names[No_Of_Employees][15];
}st_employees;
An array can be defined as a data structure where we can group the variables of same data types. Each element of the array can be char, int, double, float or even a structure. We know a structure allows elements of diverse data types to be grouped under a single name.
A variable length array, which is a C99 feature, is an array of automatic storage duration whose length is determined at run time.
A flexible array member is a C99 feature and can be used to access a variable-length object. It is declared with an empty index, as follows: array_identifier[ ]; For example, b is a flexible array member of Foo . struct Foo { int a; int b[]; };
If coding in C99 or C11, you might want to use flexible array members (you don't give an explicit dimension, but you should have a convention about it at runtime in your head).
typedef struct {
unsigned No_Of_Employees;
char* Employee_Names[]; // conventionally with No_of_Employees slots
}st_employees;
As for any array, each slot of a flexible array member has a fixed size. I'm using a pointer (e.g. 8 bytes on my Linux/x86-64 machine).
(In old compilers before the C99 standards, you might try give a 0
dimension like char* Employee_Names[0];
even if it is against the standard)
Then you would allocate such a structure using e.g.
st_employees* make_employees(unsigned n) {
st_employees* s = malloc(sizeof(s_employees)+n*sizeof(char*));
if (!s) { perror("malloc make_employees"); exit(EXIT_FAILURE); };
s->No_of_Employees = n;
for (unsigned i=0; i<n; i++) s->Employe_Names[i] = NULL;
return s;
}
and you might use (with strdup(3) duplicating a string in the heap) it like
st_employees* p = make_employees(3);
p->Employee_Names[0] = strdup("John");
p->Employee_Names[1] = strdup("Elizabeth");
p->Employee_Names[2] = strdup("Brian Kernighan");
You'll need a void destroy_employee(st_employee*e)
function (left as an exercise to the reader). It probably should loop on i
to free
every e->Employee_Names[i]
, then free(e);
...
Don't forget to document the conventions about memory usage (who is in charge of calling malloc
and free
). Read more about C dynamic memory allocation (and be scared of memory fragmentation and buffer overflows and any other undefined behavior).
If using a GCC older than GCC 5 be sure to compile with gcc -std=c99 -Wall
since the default standard for old GCC 4 compilers is C89. For newer compilers, ask for all warnings and more of them, e.g. gcc -Wall -Wextra
...
TL;DR answer - No, you cannot.
To elaborate, let me quote C11
, chapter §6.7.2.1, Structure and union specifiers
(emphasis mine)
A member of a structure or union may have any complete object type other than a variably modified type. [...]
and, a VLA is a variably modified type.
However, quoting from the same standard, regarding the flexible array member
As a special case, the last element of a structure with more than one named member may have an incomplete array type; this is called a flexible array member. [...]
So, you can do something like
typedef struct
{
uint8_t No_Of_Employees;
uint8_t* Employee_Names[];
}st_employees;
and later, you can allocate memory dynamically at the runtime to Employee_Names
(and Employee_Names[i]
, too) and make use of it.
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With