Can lapply pass (to a function) values stored in a vector, successively

Question

I need lapply to pass (to a function) values stored in a vector, successively.

values <- c(10,11,13,10)
lapply(foo,function(x) peakabif(x,npeaks=values))

So to get :

peakabif(x1,npeaks=10)
peakabif(x2,npeaks=11)
peakabif(x3,npeaks=13)
peakabif(x4,npeaks=10)

Is this possible or do I need to reconsider using lapply ? Is a for loop inside the function would work ?

Answer 1

You want to use mapply for this: mapply(peakabif, x=foo, npeaks=values)