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Say I have a struct like this:
struct S { int i; double d; std::string s; }; Can I do this?
std::make_shared<S>(1, 2.1, "Hello") 
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As well as this efficiency, using make_shared means that you don't need to deal with new and raw pointers at all, giving better exception safety - there is no possibility of throwing an exception after allocating the object but before assigning it to the smart pointer.
std::make_sharedAllocates and constructs an object of type T passing args to its constructor, and returns an object of type shared_ptr<T> that owns and stores a pointer to it (with a use count of 1). This function uses ::new to allocate storage for the object.
No you can't, you have to define your own constructor for being able to do it.
#include <iostream> #include <memory> #include <string> struct S { S(int ii, double dd) : i(ii) , d(dd) { } int i; double d; }; int main() { // S s{1, 2.1}; auto s = std::make_shared<S>(1, 2.1); //or without constructor, you have to create manually a temporary auto s1 = std::make_shared<S>(S{1, 2.1}); } If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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