Can I use std::make_shared with structs that don't have a parametric constructor?

Question

Say I have a struct like this:

struct S { int i; double d; std::string s; }; 

Can I do this?

std::make_shared<S>(1, 2.1, "Hello") 

Answer 1

No you can't, you have to define your own constructor for being able to do it.

#include <iostream> #include <memory> #include <string>  struct S {     S(int ii, double dd)     : i(ii)     , d(dd)     { }   int i;   double d; };  int main() {  // S s{1, 2.1};   auto s = std::make_shared<S>(1, 2.1);   //or without constructor, you have to create manually a temporary   auto s1 = std::make_shared<S>(S{1, 2.1});  }