Can I use `map` with fixed input?

Question

Suppose I do f(x,y) = 2x + ythen map(f, [2,4,6],[1,1,1]) I will get:

3-element Array{Int64,1}:
  5
  9
 13

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If I do map(f, [2,4,6],1), i.e., I want to suppose that the second input is always the same, I will get:

1-element Array{Any,1}:
5

So this does not work. Is there a way to do this without coding a Vector [1,1,1] ?

Answer 1

Broadcast "acts like" it changes the arrays to be a size which works, and maps:

broadcast(f, [2,4,6],1)

outputs:

Int64[3]
5
9
13

Answer 2

You can use map(x->f(x,1), [2,4,6]) to accomplish this.