Can I use $1 in regex_replace?

Question

From reading the FCD for regex_replace (28.11.4) I can only guess that the function can also use parts of the original string for replacing? I can not test it with my gcc, is this correct?

using namespace std;
regex rx{ R"((\d+)-(\d+))" }; // regex: (\d+)-(\d+)
cout << regex_replace("123-456", rx, "b: $2, a:$1");
// "b: 456, a:123"

As you can see, I assume $1 and $2 refer to the "()" capturing groups (and not \1 and \2 like elsewhere).

Update. So, I guess this is a two-part question

• Is this use of capturing groups in the replacement text supported at all?
• Is the default ECMAScript syntax using $n? Or \n?

Answer 1

Table 139 in the C++ 2011 FDIS lists two constants that can be used to affect the rules used for the format string in regex_replace, format_default and format_sed. format_default is described as using "the rules used by the ECMAScript replace function in ECMA-262, part 15.5.4.11 String.prototype.replace." This standard does indicate the use of $ for backreferences. See: ECMA-262

Using the format_sed flag instead uses the rules for the sed utility in POSIX. Sed doesn't appear to support $ backreferences.