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In a verbatim string literal (@"foo") in C#, backslashes aren't treated as escapes, so doing \" to get a double quote doesn't work. Is there any way to get a double quote in a verbatim string literal?
This understandably doesn't work:
string foo = @"this \"word\" is escaped"; 
547
To escape a single or double quote in a string, use a backslash \ character before each single or double quote in the contents of the string, e.g. 'that\'s it' .
A "string literal" is a sequence of characters from the source character set enclosed in double quotation marks (" "). String literals are used to represent a sequence of characters which, taken together, form a null-terminated string. You must always prefix wide-string literals with the letter L.
String literal syntaxUse the escape sequence \n to represent a new-line character as part of the string. Use the escape sequence \\ to represent a backslash character as part of the string. You can represent a single quotation mark symbol either by itself or with the escape sequence \' .
A verbatim string literal consists of an @ character followed by a double-quote character, zero or more characters, and a closing double-quote character. A simple example is @"hello".
Use a duplicated double quote.
@"this ""word"" is escaped"; outputs:
this "word" is escaped Use double quotation marks.
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