C/C++: Can I access static variables inside a function from outside? For example:
#include <iostream>
using namespace std;
void f()
{
static int count = 3;
cout << count << endl;
}
int main(int argc, char** argv)
{
f::count = 5; // apparently this is an invalid syntax.
f();
return 0;
}
Static variables in methods i.e. you cannot use a local variable outside the current method which contradicts with the definition of class/static variable. Therefore, declaring a static variable inside a method makes no sense, if you still try to do so, a compile time error will be generated.
We cannot access non-static variables or instance variables inside a static method. Because a static method can be called even when no objects of the class have been instantiated.
private static variable is shared, but not accessible outside the class. public non-static variable is not shared, but accessible outside the class. private non-static variable is neither shared nor accessible outside the class.
Static Function MembersA static member function can only access static data member, other static member functions and any other functions from outside the class. Static member functions have a class scope and they do not have access to the this pointer of the class.
No, you can't, neither in C nor in C++.
If you want to maintain state associated with a function, define a class with the appropriate state and a member function. (In C++. You've also tagged the question with C; the same technique works but you need to do all the groundwork yourself.)
Although they have their uses, most of the time non-const static locals are a bad idea. They make your function thread-unsafe, and they often make it "call-once".
Variables inside a function scope cannot be accessed externally by name, but you can return a pointer or reference to it
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