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Can bin() be overloaded like oct() and hex() in Python 2.6?

In Python 2.6 (and earlier) the hex() and oct() built-in functions can be overloaded in a class by defining __hex__ and __oct__ special functions. However there is not a __bin__ special function for overloading the behaviour of Python 2.6's new bin() built-in function.

I want to know if there is any way of flexibly overloading bin(), and if not I was wondering why the inconsistent interface?

I do know that the __index__ special function can be used, but this isn't flexible as it can only return an integer. My particular use case is from the bitstring module, where leading zero bits are considered significant:

>>> a = BitString(length=12)       # Twelve zero bits
>>> hex(a)
'0x000'
>>> oct(a)
'0o0000'
>>> bin(a)
'0b0' <------ I want it to output '0b000000000000'

I suspect that there's no way of achieving this, but I thought it wouldn't hurt to ask!

like image 868
Scott Griffiths Avatar asked Jun 16 '09 15:06

Scott Griffiths


3 Answers

As you've already discovered, you can't override bin(), but it doesn't sound like you need to do that. You just want a 0-padded binary value. Unfortunately in python 2.5 and previous, you couldn't use "%b" to indicate binary, so you can't use the "%" string formatting operator to achieve the result you want.

Luckily python 2.6 does offer what you want, in the form of the new str.format() method. I believe that this particular bit of line-noise is what you're looking for:

>>> '{0:010b}'.format(19)
'0000010011'

The syntax for this mini-language is under "format specification mini-language" in the docs. To save you some time, I'll explain the string that I'm using:

  1. parameter zero (i.e. 19) should be formatted, using
  2. a magic "0" to indicate that I want 0-padded, right-aligned number, with
  3. 10 digits of precision, in
  4. binary format.

You can use this syntax to achieve a variety of creative versions of alignment and padding.

like image 88
Glyph Avatar answered Oct 13 '22 18:10

Glyph


I think the short answer is 'No, bin() can't be overloaded like oct() and hex().'

As to why, the answer must lie with Python 3.0, which uses __index__ to overload hex(), oct() and bin(), and has removed the __oct__ and __hex__ special functions altogether.

So the Python 2.6 bin() looks very much like it's really a Python 3.0 feature that has been back-ported without much consideration that it's doing things the new Python 3 way rather than the old Python 2 way. I'd also guess that it's unlikely to get fixed, even if it is considered to be a bug.

like image 35
Scott Griffiths Avatar answered Oct 13 '22 18:10

Scott Griffiths


The bin function receives it's value from the object's __index__ function. So for an object, you can define the value converted to binary, but you can't define the format of the string.

like image 1
Michael Mior Avatar answered Oct 13 '22 19:10

Michael Mior