call printf using va_list

Question

void TestPrint(char* format, ...) {     va_list argList;      va_start(argList, format);     printf(format, argList);     va_end(argList); }   int main() {     TestPrint("Test print %s %d\n", "string", 55);     return 0; } 

I need to get:

Test print string 55 

Actually, I get garbage output. What is wrong in this code?

Answer 1

Use vprintf() instead.

Answer 2

Instead of printf, I recommend you try vprintf instead, which was created for this specific purpose:

#include <stdio.h> #include <stdlib.h> #include <stdarg.h>  void errmsg( const char* format, ... ) {     va_list arglist;      printf( "Error: " );     va_start( arglist, format );     vprintf( format, arglist );     va_end( arglist ); }  int main( void ) {     errmsg( "%s %d %s", "Failed", 100, "times" );     return EXIT_SUCCESS; } 

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