Call PowerShell script PS1 from another PS1 script inside Powershell ISE

Question

In order to find the location of a script, use Split-Path $MyInvocation.MyCommand.Path (make sure you use this in the script context).

The reason you should use that and not anything else can be illustrated with this example script.

## ScriptTest.ps1
Write-Host "InvocationName:" $MyInvocation.InvocationName
Write-Host "Path:" $MyInvocation.MyCommand.Path

Here are some results.

PS C:\Users\JasonAr> .\ScriptTest.ps1
InvocationName: .\ScriptTest.ps1
Path: C:\Users\JasonAr\ScriptTest.ps1

PS C:\Users\JasonAr> . .\ScriptTest.ps1
InvocationName: .
Path: C:\Users\JasonAr\ScriptTest.ps1

PS C:\Users\JasonAr> & ".\ScriptTest.ps1"
InvocationName: &
Path: C:\Users\JasonAr\ScriptTest.ps1

In PowerShell 3.0 and later you can use the automatic variable $PSScriptRoot:

## ScriptTest.ps1
Write-Host "Script:" $PSCommandPath
Write-Host "Path:" $PSScriptRoot

PS C:\Users\jarcher> .\ScriptTest.ps1
Script: C:\Users\jarcher\ScriptTest.ps1
Path: C:\Users\jarcher

I am calling myScript1.ps1 from myScript2.ps1 .

Assuming both of the script are at the same location, first get the location of the script by using this command :

$PSScriptRoot

And, then, append the script name you want to call like this :

& "$PSScriptRoot\myScript1.ps1"

This should work.

The current path of MyScript1.ps1 is not the same as myScript2.ps1. You can get the folder path of MyScript2.ps1 and concatenate it to MyScript1.ps1 and then execute it. Both scripts must be in the same location.

## MyScript2.ps1 ##
$ScriptPath = Split-Path $MyInvocation.InvocationName
& "$ScriptPath\MyScript1.ps1"

One line solution:

& ((Split-Path $MyInvocation.InvocationName) + "\MyScript1.ps1")