call of overloaded 'swap(float&, float&)' is ambiguous

Question

in this program the calling of swap function giving an error called call of overloded function is ambiguos.please tell me how i can resolve this problem. is there is any diffrent method of calling the template function

     #include<iostream>
    using namespace std;
      template <class T>
    void swap(T&x,T&y)
    {
            T temp;
            temp=x;
         x=y;
           y=temp;
       }
    int main()
   {
    float f1,f2;
    cout<<"enter twp float numbers: ";
    cout<<"Float 1: ";
     cin>>f1;
    cout<<"Float 2: ";
    cin>>f2;
    swap(f1,f2);
    cout<<"After swap: float 1: "<<f1<<" float 2:"<<f2;
    int a,b;
    cout<<"enter twp integer numbers: ";
    cout<<"int 1: ";
    cin>>a;
    cout<<"int 2: ";
    cin>>b;
    swap(a,b);
    cout<<"After swap: int 1: "<<a<<" int 2:"<<b;
    return 0;
    }

Answer 1

Your function is conflicting with the one defined in move.h that is included implicitly by some of your includes. If you remove the using namespace std this should be fixed - the function you are conflicting with is defined in the std namespace.

Answer 2

By changing the swap function to my_swap function it solve the problem. because swap is also a predefined function in c++

#include<iostream>
using namespace std;
  template <class T>
void my_swap(T&x,T&y)
{
        T temp;
        temp=x;
     x=y;
       y=temp;
   }
int main()
{
  float f1,f2;
cout<<"enter twp float numbers: ";
cout<<"Float 1: ";
 cin>>f1;
cout<<"Float 2: ";
cin>>f2;
my_swap(f1,f2);
cout<<"After swap: float 1: "<<f1<<" float 2:"<<f2;
int a,b;
cout<<"enter twp integer numbers: ";
cout<<"int 1: ";
cin>>a;
cout<<"int 2: ";
cin>>b;
my_swap(a,b);
cout<<"After swap: int 1: "<<a<<" int 2:"<<b;
return 0;
}