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I got stuck in part of the script. I have time: for example "16:00" and duration in minutes like: 410.
Is there any easy way to add those two values? I've tried a lot of combinations with date -d, but can't solve it.
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Then, we used the $SECONDS variable, which is the Bash shell's internal variable that holds the elapsed time since the current shell started. After that, we used the TIMEFORMAT built-in variable along with the %R option for calculating the elapsed time with millisecond precision.
Use unix time instead, date +%s , then subtract to get the difference in seconds.
In bash , it removes a prefix pattern. Here, it's basically giving you everything after the last path separator / , by greedily removing the prefix */ , any number of characters followed by / ): pax> fspec=/path/to/some/file.txt ; echo ${fspec##*/} file.txt. Greedy in this context means matches as much as possible.
date +%S. Displays seconds [00-59] date +%N. Displays in Nanoseconds. date +%T.
Try this (Kysu's version):
date -d "16:00 410 minutes" +'%H:%M'
or this:
date -d "16:00 today + 410 minutes" +'%H:%M'
But do not use this:
date -d "16:00 + 410 minutes" +'%H:%M' # BAD!
Strange things happen if you omit the word today but keep the +. (I think the + 410 is being parsed as a timezone modifier, and then the minutes is interpreted as "add one minute".)
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