I need to calculate the volume of a tetrahedron given the coordinates of its four corner points.
A tetrahedron has four faces, six edges and four vertices. Its three edges meet at each vertex. The four vertices that we have been given in the question are A(1,1,0) B(-4,3,6) C(-1,0,3) and D(2,4,-5). Hence, the volume of the given tetrahedron is 6 cubic units.
The volume of the tetrahedron is one third the product of its base and its height, the latter of which is . Therefore, \displaystyle V = \frac{1}{3} \cdot 9n \cdot 2n^{2} = 6 n^{3}.
Say if you have 4 vertices a,b,c,d (3-D vectors).
Now, the problem comes down to writing code which solves cross product and dot product of vectors. If you are from python, you can use NumPy or else you can write code on your own.
The Wikipedia link should definitely help you. LINK
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With