I have the following query:
db.getCollection('user').aggregate([
{$unwind: "$education"},
{$project: {
duration: {"$divide":[{$subtract: ['$education.to', '$education.from'] }, 1000 * 60 * 60 * 24 * 365]}
}},
{$group: {
_id: '$_id',
"duration": {$sum: '$duration'}
}}]
])
Above query result is:
{
"_id" : ObjectId("59fabb20d7905ef056f55ac1"),
"duration" : 2.34794520547945
}
/* 2 */
{
"_id" : ObjectId("59fab630203f02f035301fc3"),
"duration" : 2.51232876712329
}
But what I want to do is get its duration in year
+ month
+ day
format, something like: 2 y, 3 m, 20 d
.
One another point, if a course is going on the to
field is null, and another field isGoingOn: true
, so here I should calculate the duration by using current date instead of to
field.
And user has array of course subdocuments
education: [
{
"courseName": "Java",
"from" : ISODate("2010-12-08T00:00:00.000Z"),
"to" : ISODate("2011-05-31T00:00:00.000Z"),
"isGoingOn": false
},
{
"courseName": "PHP",
"from" : ISODate("2013-12-08T00:00:00.000Z"),
"to" : ISODate("2015-05-31T00:00:00.000Z"),
"isGoingOn": false
},
{
"courseName": "Mysql",
"from" : ISODate("2017-02-08T00:00:00.000Z"),
"to" : null,
"isGoingOn": true
}
]
One another point is this: that date may be not continuous in one subdocument to the other subdocument. A user may have a course for 1 year, and then after two years, he/she started his/her next course for 1 year, and 3 months (it means this user has a total of 2 years and 3-month course duration).
What I want is get date difference of each subdocument in educations array, and sum those. Suppose in my sample data Java
course duration is 6 month, and 22 days, PHP
course duration is 1 year, and 6 months, and 22 days, and the last one is from 8 Feb 2017 till now, and it's going on, so my education duration is the sum of these intervals.
In a new cell, type in =DATEDIF(A1,B1,”Y”). The “Y” signifies that you'd like the information reported in years. This will give you the number of years between the two dates. To find the number of months or days between two dates, type into a new cell: =DATEDIF(A1,B1,”M”) for months or =DATEDIF(A1,B1,”D”) for days.
Just subtract one date from the other. For example if cell A2 has an invoice date in it of 1/1/2015 and cell B2 has a date paid of 1/30/2015, then you could enter use the formula =B2-A2 to get the number of days between the two dates, or 29.
Please try this aggregation to get date difference in days,months and years, added multiple $addFields
stage compute and reduce differences to date, month range without underflow, and the assumption here is 1 month = 30 days
pipeline
db.edu.aggregate(
[
{
$addFields : {
trainingPeriod : {
$map : {
input : "$education",
as : "t",
in : {
year: {$subtract: [{$year : {$ifNull : ["$$t.to", new Date()]}}, {$year : "$$t.from"}]},
month: {$subtract: [{$month : {$ifNull : ["$$t.to", new Date()]}}, {$month : "$$t.from"}]},
dayOfMonth: {$subtract: [{$dayOfMonth : {$ifNull : ["$$t.to", new Date()]}}, {$dayOfMonth : "$$t.from"}]}
}
}
}
}
},
{
$addFields : {
trainingPeriod : {
$map : {
input : "$trainingPeriod",
as : "d",
in : {
year: "$$d.year",
month: {$cond : [{$lt : ["$$d.dayOfMonth", 0]}, {$subtract : ["$$d.month", 1]}, "$$d.month" ]},
day: {$cond : [{$lt : ["$$d.dayOfMonth", 0]}, {$add : [30, "$$d.dayOfMonth"]}, "$$d.dayOfMonth" ]}
}
}
}
}
},
{
$addFields : {
trainingPeriod : {
$map : {
input : "$trainingPeriod",
as : "d",
in : {
year: {$cond : [{$lt : ["$$d.month", 0]}, {$subtract : ["$$d.year", 1]}, "$$d.year" ]},
month: {$cond : [{$lt : ["$$d.month", 0]}, {$add : [12, "$$d.month"]}, "$$d.month" ]},
day: "$$d.day"
}
}
}
}
},
{
$addFields : {
total : {
$reduce : {
input : "$trainingPeriod",
initialValue : {year : 0, month : 0, day : 0},
in : {
year: {$add : ["$$this.year", "$$value.year"]},
month: {$add : ["$$this.month", "$$value.month"]},
day: {$add : ["$$this.day", "$$value.day"]}
}
}
}
}
},
{
$addFields : {
total : {
year : "$total.year",
month : {$add : ["$total.month", {$floor : {$divide : ["$total.day", 30]}}]},
day : {$mod : ["$total.day", 30]}
}
}
},
{
$addFields : {
total : {
year : {$add : ["$total.year", {$floor : {$divide : ["$total.month", 12]}}]},
month : {$mod : ["$total.month", 12]},
day : "$total.day"
}
}
}
]
).pretty()
result
{
"_id" : ObjectId("5a895d4721cbd77dfe857f95"),
"education" : [
{
"courseName" : "Java",
"from" : ISODate("2010-12-08T00:00:00Z"),
"to" : ISODate("2011-05-31T00:00:00Z"),
"isGoingOn" : false
},
{
"courseName" : "PHP",
"from" : ISODate("2013-12-08T00:00:00Z"),
"to" : ISODate("2015-05-31T00:00:00Z"),
"isGoingOn" : false
},
{
"courseName" : "Mysql",
"from" : ISODate("2017-02-08T00:00:00Z"),
"to" : null,
"isGoingOn" : true
}
],
"trainingPeriod" : [
{
"year" : 0,
"month" : 5,
"day" : 23
},
{
"year" : 1,
"month" : 5,
"day" : 23
},
{
"year" : 1,
"month" : 0,
"day" : 10
}
],
"total" : {
"year" : 2,
"month" : 11,
"day" : 26
}
}
>
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