C# Regular Expression: Remove leading and trailing double quotes (")

Question

If I have a string like below... what is the regular expression to remove the (optional) leading and trailing double quotes? For extra credit, can it also remove any optional white space outside of the quotes:

string input = "\"quoted string\""   -> quoted string
string inputWithWhiteSpace = "  \"quoted string\"    "  => quoted string

(for C# using Regex.Replace)

Answer 1

It's overkill to use Regex.Replace for this. Use Trim instead.

string output = input.Trim(' ', '\t', '\n', '\v', '\f', '\r', '"');

And if you only want to remove whitespace that's outside the quotes, retaining any that's inside:

string output = input.Trim().Trim('"');