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C++ regex for overlapping matches

Tags:

c++

regex

greedy

I have a string 'CCCC' and I want to match 'CCC' in it, with overlap.

My code:

...
std::string input_seq = "CCCC";
std::regex re("CCC");
std::sregex_iterator next(input_seq.begin(), input_seq.end(), re);
std::sregex_iterator end;
while (next != end) {
    std::smatch match = *next;
    std::cout << match.str() << "\t" << "\t" << match.position() << "\t" << "\n";
    next++;
}
...

However this only returns

CCC 0 

and skips the CCC 1 solution, which is needed for me.

I read about non-greedy '?' matching, but I could not make it work

like image 740
Gábor Erdős Avatar asked Mar 10 '23 10:03

Gábor Erdős


1 Answers

Your regex can be put into the capturing parentheses that can be wrapped with a positive lookahead.

To make it work on Mac, too, make sure the regex matches (and thus consumes) a single char at each match by placing a . (or - to also match line break chars - [\s\S]) after the lookahead.

Then, you will need to amend the code to get the first capturing group value like this:

#include <iostream>
#include <regex>
#include <string>
using namespace std;

int main() {
    std::string input_seq = "CCCC";
    std::regex re("(?=(CCC))."); // <-- PATTERN MODIFICATION
    std::sregex_iterator next(input_seq.begin(), input_seq.end(), re);
    std::sregex_iterator end;
    while (next != end) {
        std::smatch match = *next;
        std::cout << match.str(1) << "\t" << "\t" << match.position() << "\t" << "\n"; // <-- SEE HERE
        next++;
    }
    return 0;
}

See the C++ demo

Output:

CCC     0   
CCC     1   
like image 86
Wiktor Stribiżew Avatar answered Mar 19 '23 15:03

Wiktor Stribiżew