C preprocessor: How to create a character literal?

Question

Just out of curiosity, I'd like to know if it is possible to define a macro which can turn its argument into a character literal:

 switch(getchar()) {
   case MYMACRO(A): printf("Received A\n"); break;
   case MYMACRO(a): printf("Received a\n"); break;
   case MYMACRO(!): printf("Received an exclamation mark\n"); break;
   default: printf("Neither a nor A nor !\n"); break;
 }

Two possible solutions off the top of my head:

Enumerating all characters

#define LITERAL_a 'a'
#define LITERAL_b 'b'
...
#define MYMACRO(x) LITERAL_ ## x

It doesn't work with MYMACRO(!) because ! is not a valid component of a C identifier.

Convert the parameter into a string literal

#define MYMACRO(x) #x [0]

It involves a pointer dereference and is invalid in places like a case label.

I'm not asking for a way to "improve" the above switch statement itself. It's just a toy example. Repeat. It's just a toy example.

Answer 1

While I couldn't get user4098326's answer to compile, I did get the solution below to compile and work as expected (in Code Composer Studio). The key was to use the symbol concatenation operator. Note however, that according to the standard, this should not work. A single quote (') is not a valid token nor is a single quote followed by a single character ('a). Thus those should not be able to be the input nor output of the concatenation operator. Thus, I would not recommend actually using this solution.

#define CONCAT_H(x,y,z) x##y##z
#define SINGLEQUOTE '
#define CONCAT(x,y,z) CONCAT_H(x,y,z)
#define CHARIFY(x) CONCAT(SINGLEQUOTE , x , SINGLEQUOTE )

#define DO_CASE(...) case CHARIFY(__VA_ARGS__): printf("Got a " #__VA_ARGS__ "\n"); break

Then:

switch(getchar()) {
   DO_CASE(A);
   DO_CASE(a);
   DO_CASE(!);
   default: printf("Neither a nor A nor !\n"); break;
 }