C++ Pass an object into another object?

Question

I don't know if I've missed something, but I can't seem to figure out how to make this work, and couldn't find the answer online.

Lets say I have a two classes, Class A, and Class B. (stored in separate files)

Class A has a function setName() that sets a variable within a Class A object.

Class B has a function setOtherName() that sets the value of a Class A object's name.

So I set setOtherName() up like so:

void setOtherName(ClassA& cla)
{
*cla.setName("foobar");
}

then my main script looks like so:

Class A burger;
Class B fries;
fries.setOtherName(*burger);

this does not work in my orignal script, I get the following error:

error: no matching function for call to 'ClassB::setOtherName(ClassA*&)

Any help is aprreciated! ( sorry for any confusion )

Actual code: main.cpp:

#include <iostream>
#include "quests.h"
#include "player.h"
#include <string>
#include <cstdlib>

using namespace std;

int main()
{
    quests GameQuests;
    player Player;
    GameQuests.quest1(Player);
    Player.main();

    return 0;
}

quests.cpp:

#include "quests.h"
#include "player.h"
#include <iostream>
#include <string>
#include <cstdlib>
using namespace std;

void quests::quest1(player& charact){
    cout << "By the way, what was your name?" << endl;
    person1=4;
    system("pause");
    charact->setName();
}

Answer 1

The implementation of your setOtherName function should have the signature

void ClassB::setOtherName(ClassA& cla)

You need to specify that it is included in ClassB. Within your class definition of ClassB, make sure to include

void setOtherName(ClassA&);

Furthermore, since your variable burger is of type ClassA and not of type ClassA*, there is no need to dereference the variable upon passing it into the function. Call it like

fries.setOtherName(burger);

You have also incorrectly dereferenced the variable cla. That object is passed by reference, not pointer, so there is no need to dereference.