I have a set of strings, and I want to find all possible combinations of the strings and add them to a list. I want to end up with a list of a list of each combination of the strings, minus the empty set.
I have created a solution that does this exactly with a nested for loop. However I want to do this more elegantly, preferably with LINQ, and I am not so proficient with it because I'm still pretty new to it.
The solution should have 2^n - 1 lists of combinations where n is the cardinality of the original set. Here is a correct example of what I am looking for:
set = {a, b, c}
completedListOfCombinations =
{
{a},
{b},
{a, b},
{c},
{a, c},
{b, c},
{a, b, c}
}
Here is my working, basic but ugly solution that I crafted with help from: https://stackoverflow.com/a/3319652/3371287
List<string> myStrings = new List<string> { "a", "b", "c" };
var allCombos = new List<List<string>>();
for (int i = 0; i < myStrings.Count; i++)
{
int subsetCount = allCombos.Count;
var m = new List<string>();
m.Add(myStrings[i]);
allCombos.Add(m);
for (int j = 0; j < subsetCount; j++)
{
string[] subset = new string[allCombos.ElementAt(j).Count + 1];
allCombos[j].CopyTo(subset, 0);
subset[subset.Length - 1] = myStrings[i];
allCombos.Add(subset.ToList());
}
}
Can someone show me a more elegant solution for this? I have seen similar LINQ solutions that create Cartesian Pairs and lists with a threshold, but I have not been able to tweak them to what I need.
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Providing that all the values in the list
are unique:
List <String> list = new List<String> { "a", "b", "c" };
var result = Enumerable
.Range(1, (1 << list.Count) - 1)
.Select(index => list.Where((item, idx) => ((1 << idx) & index) != 0).ToList());
To print out:
Console.WriteLine(String
.Join(Environment.NewLine, result
.Select(line => String.Join(", ", line))));
The outcome is
a
b
a, b
c
a, c
b, c
a, b, c
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