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C# lambda unnamed parameters

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is it possible, to discard some arguments in lambda expressions by don't give them a name? E.g. I have to pass a Action<int,int>, but I'm only interested in the second param, i want to write something like

(_, foo) => bar(foo) // or (, foo) => bar(foo) 

In the first case it is working. But the first parameter isn't really unnamed, because it has the name "_". So it isn't working, when I want to discard two or more. I choose _ because in prolog it has the meaning "any value".

So. Is there any special character or expression for my use case?

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Sven-Michael Stübe Avatar asked Dec 10 '12 07:12

Sven-Michael Stübe


1 Answers

No, you can't. Looking at the C# language specification grammar, there are two ways to declare lambdas: explicit and implicit. Neither one allows you to skip the identifier of the parameter or to reuse identifiers (names).

explicit-anonymous-function-parameter:   anonymous-function-parameter-modifieropt   type   identifier  implicit-anonymous-function-parameter:   identifier 

It's the same as for unused function parameters in ordinary functions. They have to be given a name.

Of course you can use _ as the name for one of the parameters, as it is a valid C# name, but it doesn't mean anything special.

As of C# 7, _ does have a special meaning. Not for lambda expression parameter names but definitely for other things, such as pattern matching, deconstruction, out variables and even regular assignments. (For example, you can use _ = 5; without declaring _.)

like image 71
Anders Abel Avatar answered Sep 17 '22 16:09

Anders Abel