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I have this method in my java code which returns byte array for given int:
private static byte[] intToBytes(int paramInt) { byte[] arrayOfByte = new byte[4]; ByteBuffer localByteBuffer = ByteBuffer.allocate(4); localByteBuffer.putInt(paramInt); for (int i = 0; i < 4; i++) arrayOfByte[(3 - i)] = localByteBuffer.array()[i]; return arrayOfByte; } Can someone give me tip how can i convert that method to C++?
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We split the input integer (5000) into each byte by using the >> operator. The second operand represents the lowest bit index for each byte in the array. To obtain the 8 least significant bits for each byte, we & the result with 0xFF . Finally, we print each byte using the print function.
An int value can be converted into bytes by using the method int. to_bytes().
In C, you can uses casts to convert between types. That's not called a typecast, however. The C language specification generally frowns upon type punning, where you access an object of one type through a pointer of another type. There are a handful of exceptions.
A byte array is simply a collection of bytes. The bytearray() method returns a bytearray object, which is an array of the specified bytes. The bytearray class is a mutable array of numbers ranging from 0 to 256.
You don't need a whole function for this; a simple cast will suffice:
int x; static_cast<char*>(static_cast<void*>(&x)); Any object in C++ can be reinterpreted as an array of bytes. If you want to actually make a copy of the bytes into a separate array, you can use std::copy:
int x; char bytes[sizeof x]; std::copy(static_cast<const char*>(static_cast<const void*>(&x)), static_cast<const char*>(static_cast<const void*>(&x)) + sizeof x, bytes); Neither of these methods takes byte ordering into account, but since you can reinterpret the int as an array of bytes, it is trivial to perform any necessary modifications yourself.
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